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NEW QUESTION: 1
HOTSPOT
You manage a Microsoft-SQL Server database named sales Orders.
You need to verify the integrity of the database and attempt to repair any errors that are found. Repair must not cause any data to be lost in the database.
How should you complete the DBCC command? To answer, select the appropriate options in the answer area.

Answer:
Explanation:

Explanation:

Box 1: CHECKDB
DBCC CHECKDB checks the logical and physical integrity of all the objects in the specified database.
Partial syntax:
DBCC CHECKDB
[ ( database_name | database_id | 0
[ , NOINDEX
| , { REPAIR_ALLOW_DATA_LOSS | REPAIR_FAST | REPAIR_REBUILD } ]
... .
Box 2: REPAIR_REBUILD
DBCC CHECKDB ...REPAIR_ALLOW_DATA_LOSS | REPAIR_FAST |REPAIR_REBUILD
specifies that DBCC CHECKDB repair the found errors.
REPAIR_REBUILD performs repairs that have no possibility of data loss. This can include quick repairs, such as repairing missing rows in non-clustered indexes, and more time- consuming repairs, such as rebuilding an index.
References: https://docs.microsoft.com/en-us/sql/t-sql/database-console-commands/dbcc- checkdb-transact-sql

NEW QUESTION: 2
You have a database that includes the following tables:

You need to create a list of all customer IDs and the date of the last order that each customer placed. If the customer has not placed any orders, you must return the date January 1, 1900. The column names must be CustomerID and LastOrderDate.
Which four Transact-SQL segments should you use to develop the solution? To answer, move the appropriate Transact-SQL segments from the list of Transact-SQL segments to the answer area and arrange them in the correct order.

Answer:
Explanation:

Explanation

Box 1: SELECT..COALESCE...
The COALESCE function evaluates the arguments in order and returns the current value of the first expression that initially does not evaluate to NULL.
Box 2: ..LEFT OUTER JOIN..
The LEFT JOIN (LEFT OUTER JOIN) keyword returns all rows from the left table (table1), with the matching rows in the right table (table2). The result is NULL in the right side when there is no match. A customer might have no orders so the right table must be allowed have a NULL value.
Box 3: ON c.custid = o.custid
We JOIN on the custID column, which is available in both tables.
Box 4: GROUP BY c.custid
References:
https://technet.microsoft.com/en-us/library/ms189499(v=sql.110).aspx
http://www.w3schools.com/sql/sql_join_left.asp

NEW QUESTION: 3

A. Option B
B. Option A
C. Option C
D. Option D
Answer: B,D

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