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NEW QUESTION: 1
귀사는 AWS KMS 서비스를 사용하여 일련의 키를 생성했습니다. 각 키가 특정 서비스에만 사용되도록 해야 합니다. 예를 들어, 그들은 하나의 키가 S3 서비스에만 사용되기를 원합니다. 이것이 어떻게 달성 될 수 있습니까?
선택 해주세요:
A. S3 서비스에서만 키에 액세스 할 수 있도록 버킷 정책을 생성하십시오.
B. 키 정책에서 kms : ViaService 조건을 사용하십시오.
C. S3 서비스에서만 키에 액세스 할 수있는 1AM 정책을 만듭니다.
D. 1AM 사용자를 정의하고 키를 할당 한 다음 필요한 서비스에 권한을 할당하십시오.
Answer: B
Explanation:
Option A and B are invalid because mapping keys to services cannot be done via either the 1AM or bucket policy Option D is invalid because keys for 1AM users cannot be assigned to services This is mentioned in the AWS Documentation The kms:ViaService condition key limits use of a customer-managed CMK to requests from particular AWS services. (AWS managed CMKs in your account, such as aws/s3, are always restricted to the AWS service that created them.) For example, you can use kms:V1aService to allow a user to use a customer managed CMK only for requests that Amazon S3 makes on their behalf. Or you can use it to deny the user permission to a CMK when a request on their behalf comes from AWS Lambda.
For more information on key policy's for KMS please visit the following URL:
https://docs.aws.amazon.com/kms/latest/developereuide/policy-conditions.html The correct answer is: Use the kms:ViaServtce condition in the Key policy Submit your Feedback/Queries to our Experts

NEW QUESTION: 2
View the Exhibit and examine the structure of the CUSTOMERS and CUST_HISTORY tables.

The CUSTOMERS table contains the current location of all currently active customers. The CUST_HISTORY table stores historical details relating to any changes in the location of all current as well as previous customers who are no longer active with the company.
You need to find those customers who have never changed their address.
Which SET operator would you use to get the required output?
A. UNION ALL
B. INTERSECT
C. MINUS
D. UNION
Answer: C

NEW QUESTION: 3
What types of records can be added to Salesforce from Data.com?(Select all that apply)
A. Campaigns
B. Accounts
C. Contacts
D. Opportunities
E. Leads
Answer: B,C,E

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