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Exam Code:
FlashArray-Implementation-Specialist
Exam Name:
Pure Storage Certified FlashArray Implementation Specialist
Questions:
94 Q&A
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NEW QUESTION: 1
Refer to the exhibit.

You have configured two route-map instances on R1. which passes traffic from switch 1 on both VLAN 1 and VLAN 2 You wish to ensure that * The first route-map instance matches packets from VLAN 1 and sets the next hop to 3232:2/128. * The second route-map instance matches packets from VLAN 2 and sets the next hop to 3232:3/128. What feature can you implement on R1 to make this configuration possible?
A. VSSP
B. BGP local-preference
C. GLBP
D. PBR
E. BGP next-hop
Answer: D

NEW QUESTION: 2
Which two items represent data center virtualization technologies? (Choose two.)
A. VSAN
B. ECMP
C. LUN
D. GLBP
E. L2 firewall
Answer: A,C

NEW QUESTION: 3
Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply to that question.
You have a database for a banking system. The database has two tables named tblDepositAcct and tblLoanAcct that store deposit and loan accounts, respectively. Both tables contain the following columns:

You need to run a query to find the total number of customers who have both deposit and loan accounts.
Which Transact-SQL statement should you run?
A. SELECT COUNT(*)
FROM (SELECT AcctNo
FROM tblDepositAcct
INTERSECT
SELECT AcctNo
FROM tblLoanAcct) R
B. SELECT COUNT(*)
FROM tblDepositAcct D
FULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
C. SELECT COUNT (DISTINCT D.CustNo)
FROM tblDepositAcctD, tblLoanAcct L
WHERE D.CustNo = L.CustNo
D. SELECT COUNT(DISTINCT L.CustNo)
FROM tblDepositAcct D
RIGHT JOIN tblLoanAcct L ON D.CustNo = L.CustNo
WHERE D.CustNo IS NULL
E. SELECT COUNT(*)
FROM (SELECT CustNo
FROM tblDepositAcct
EXCEPT
SELECT CustNo
FROM tblLoanAcct) R
F. SELECT COUNT(*)
FROM (SELECT CustNo
FROM tblDepositAcct
UNION ALL
SELECT CustNo
FROM tblLoanAcct) R
G. SELECT COUNT(*)
FROM (SELECT CustNo
FROM tblDepositAcct
UNION
SELECT CustNo
FROM tblLoanAcct) R
H. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))
FROM tblDepositAcct D
FULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
WHERE D.CustNo IS NULL OR L.CustNo IS NULL
Answer: A
Explanation:
Explanation/Reference:
Explanation:
The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However, it only returns the rows selected by all queries or data sets. If a record exists in one query and not in the other, it will be omitted from the INTERSECT results.
References: https://www.techonthenet.com/sql/intersect.php

NEW QUESTION: 4
HOTSPOT
You need to implement Role1.
Which command should you run before you create Role1? To answer, select the appropriate options in the answer area.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

Explanation


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