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NEW QUESTION: 1
SAP developed a three phase, six step SoD Risk Management Process for use when implementing Access Risk Analysis.
Which of the following steps are a part of this process?
Note: There are 3 correct answers to this question.
A. Analysis
B. Rule Set Design
C. Risk Recognition
D. Role Building and Analysis
E. Mitigation
Answer: A,C,E

NEW QUESTION: 2
Which of the following cryptography demands less computational power and offers more security per bit?
A. Quantum cryptography
B. Elliptic Curve Cryptography (ECC)
C. Symmetric Key Cryptography
D. Asymmetric Key Cryptography
Answer: B
Explanation:
Explanation/Reference:
ECC demands less computational power and, therefore offers more security per bit. For example, an ECC with a 160-bit key offer the same security as an RSA based system with a 1024-bit key.
ECC is a variant and more efficient form of a public key cryptography (how tom manage more security out of minimum resources) gaining prominence is the ECC. ECC works well on a network computer requires strong cryptography but have some limitation such as bandwidth and processing power. This is even more important with devices such as smart cards, wireless phones and other mobile devices.
The following were incorrect answers:
Quantum Cryptography - Quantum cryptography is based on a practical application of the characteristics of the smallest "grain" of light, photons and on physical laws governing their generation, propagation and detection. Quantum cryptography is the next generation of cryptography that may solve some of the existing problem associated with current cryptographic systems, specifically the random generation and secure distribution of symmetric cryptographic keys. Initial commercial usage has already started now that the laboratory research phase has been completed.
Symmetric Encryption - Symmetric encryption is the oldest and best-known technique. A secret key, which can be a number, a word, or just a string of random letters, is applied to the text of a message to change the content in a particular way. This might be as simple as shifting each letter by a number of places in the alphabet. As long as both sender and recipient know the secret key, they can encrypt and decrypt all messages that use this key.
Asymmetric Encryption - The problem with secret keys is exchanging them over the Internet or a large network while preventing them from falling into the wrong hands. Anyone who knows the secret key can decrypt the message. One answer is asymmetric encryption, in which there are two related keys--a key pair. A public key is made freely available to anyone who might want to send you a message. A second, private key is kept secret, so that only you know it. Any message (text, binary files, or documents) that are encrypted by using the public key can only be decrypted by applying the same algorithm, but by using the matching private key. Any message that is encrypted by using the private key can only be decrypted by using the matching public key. This means that you do not have to worry about passing public keys over the Internet (the keys are supposed to be public). A problem with asymmetric encryption, however, is that it is slower than symmetric encryption. It requires far more processing power to both encrypt and decrypt the content of the message.
The following reference(s) were/was used to create this question:
CISA review manual 2014 Page number 349 and 350
http://support.microsoft.com/kb/246071

NEW QUESTION: 3

A. 0
B. 1
C. 2
D. 3
E. 4
Answer: D
Explanation:
Each octet represents eight bits. The bits, in turn, represent (from left to right): 128, 64, 32 , 16 , 8, 4, 2, 1 Add them up and you get 255. Add one for the all zeros option, and the total is 256. Now, take away one of these for the network address (all zeros) and another for the broadcast address (all ones). Each octet represents 254 possible hosts. Or 254 possible networks. Unless you have subnet zero set on your network gear, in which case you could conceivably have 255. The CIDR addressing format (/20) tells us that 20 bits are used for the network portion, so the maximum number of networks are 2

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