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NEW QUESTION: 1
A Solutions Architect is designing an architecture for a mobile gaming application. The application is expected to be very popular. The Architect needs to prevent the Amazon RDS MySQL database from becoming a bottleneck due to frequently accessed queries.
A. Multi-AZ feature on the RDS MySQL Database
B. Amazon ElastiCache in front of the RDS MySQL Database
C. Which service or feature should the Architect add to prevent a bottleneck?
D. ELB Classic Load Balancer in front of the web application tier
Answer: D

NEW QUESTION: 2
Refer to the Exhibit.

Which two statements are true? (Choose two)
A. The server has total of six vNICs
B. Server 7 in chassis 4 has been associated with profile circuit
C. To check the MAC address from server 7/4 interface eth 10 you can check the MAC addresses learned on veth 1866 on fabfic interconnect B
D. Interface vfc 1871 is pinned to fc interface 1/32 in fabric interconnect B
E. The option failover is enabled on all the interfaces
Answer: C,E

NEW QUESTION: 3
Welche der folgenden Aussagen beschreibt BEST die Ziele des Release- und Deployment-Managements?
A. Zum Aufzeichnen und Verwalten von Abweichungen, Risiken und Problemen im Zusammenhang mit dem neuen oder geänderten Service
B. Erstellen, Testen und Bereitstellen der Fähigkeit zur Bereitstellung der von Service Design angegebenen Dienste, um die Anforderungen der Stakeholder zu erfüllen und die beabsichtigten Ziele zu erreichen
C. Damit sichergestellt ist, dass alle Release- und Bereitstellungspakete nachverfolgt, installiert, getestet, verifiziert und / oder deinstalliert oder gegebenenfalls zurückgesetzt werden können
D. Um sicherzustellen, dass jedes von Service Design angegebene Release-Paket aus einer Reihe zusammengehöriger Assets und Servicekomponenten besteht, die miteinander kompatibel sind
Answer: B

NEW QUESTION: 4
Given the code fragment:
Path path1 = Paths.get("D:\\sales\\.\\quarterly\\..\\report");
path1 = path1.normalize();
Path path2 = path1.relativize(Paths.get("d:\\empdetails.dat"));
path2 = path2.resolve(path1);
System.out.println(path1);
System.out.println(path2);
}
What is the result?
A. \sales\report\empdetails.dat
B. D: \sales\quarterly\ . . .\report
C. \sales\report
D. D: \sales\report
E. \sales\report\empdetails.dat
F. D: \sales\quarterly\ . . . \report
G. \sales\report
H. D: \sales\report
Answer: D
Explanation:
Path1 is the normalized result of D:\\sales\\.\\quarterly\\..\\report
namely D: \sales\report.
The normalize method removes any redundant elements, which includes any "." or "directory/.."
occurrences.
Consider path2.
With the relativize line path2 is set to../../empdetails.dat
In this scenario the following applies to the resolve statement: Passing an absolute path to
the resolve method returns the passed-in path.So Path2 will be set to Path1 in the statementpath2
= path2.resolve(path1);
Note:
A common requirement when you are writing file I/O code is the capability to construct a path from
one location in the file system to another location. You can meet this using the relativizemethod.
This method constructs a path originating from the original path and ending at the location
specified by the passed-in path. The new path is relative to the original path.
You can combine paths by using the resolve method. You pass in a partial path , which is a path
that does not include a root element, and that partial path is appended to the original path.
Reference: The Java Tutorials,Path Operations

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