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NEW QUESTION: 1
Sie entwickeln eine Azure Cosmos DB-Lösung mithilfe der Azure Cosmos DB-SQL-API. Die Daten umfassen Millionen von Dokumenten. Jedes Dokument kann Hunderte von Eigenschaften enthalten.
Die Eigenschaften der Dokumente enthalten keine eindeutigen Werte für die Partitionierung. Azure Cosmos DB muss einzelne Container in der Datenbank skalieren, um die Leistungsanforderungen der Anwendung zu erfüllen, indem die Arbeitslast im Laufe der Zeit gleichmäßig auf alle Partitionen verteilt wird.
Sie müssen einen Partitionsschlüssel auswählen.
Welche zwei Partitionsschlüssel können Sie verwenden? Jede richtige Antwort bietet eine vollständige Lösung.
HINWEIS: Jede richtige Auswahl ist einen Punkt wert.
A. ein einzelner Eigenschaftswert, der in den Dokumenten nicht häufig vorkommt
B. Ein Hash-Suffix, das an einen Eigenschaftswert angehängt wird
C. Ein Wert, der den Sammlungsnamen enthält
D. Eine Verkettung mehrerer Eigenschaftswerte mit einem angehängten zufälligen Suffix
E. Ein einzelner Eigenschaftswert, der in den Dokumenten häufig vorkommt
Answer: B,D
Explanation:
Erläuterung:
Sie können einen Partitionsschlüssel bilden, indem Sie mehrere Eigenschaftswerte in einer einzelnen künstlichen partitionKey-Eigenschaft verketten. Diese Schlüssel werden als synthetische Schlüssel bezeichnet.
Eine andere mögliche Strategie, um die Arbeitslast gleichmäßiger zu verteilen, besteht darin, am Ende des Partitionsschlüsselwerts eine Zufallszahl anzufügen. Wenn Sie Elemente auf diese Weise verteilen, können Sie parallele Schreibvorgänge über Partitionen ausführen.
Hinweis: Es wird empfohlen, einen Partitionsschlüssel mit vielen unterschiedlichen Werten wie z. B. Hunderten oder Tausenden zu verwenden. Ziel ist es, Ihre Daten und Arbeitslast gleichmäßig auf die Elemente zu verteilen, die diesen Partitionsschlüsselwerten zugeordnet sind. Wenn eine solche Eigenschaft in Ihren Daten nicht vorhanden ist, können Sie einen synthetischen Partitionsschlüssel erstellen.
Verweise:
https://docs.microsoft.com/en-us/azure/cosmos-db/synthetic-partition-keys

NEW QUESTION: 2
What is the key difference between Electronic Codebook mode and other block cipher modes like Cipher Block Chaining, Cipher-Feedback and Output-Feedback?
A. Plaintext patterns encrypted with the same key will always generate the same Cipher text pattern
B. Plaintext patterns are concealed by XO Ring with previous cipher text block but input to the block cipher is not randomized.
C. Plaintext patterns are concealed and input to the block cipher is randomized by XO Ring with previous cipher text block.
D. Plaintext patterns are not concealed but input to the block cipher is randomized by XO Ring with previous cipher text block.
Answer: A

NEW QUESTION: 3
A company hosts a two-tier application that consists of a publicly accessible web server that communicates with a private database. Only HTTPS port 443 traffic to the web server must be allowed from the internet.
Which of the following options will achieve these requirements? (Select Two.)
A. Security group rule that allows inbound internet traffic for port 443
B. Network ACL rule that allows port 443 for both inbound and outbound for all Internet traffic
C. Security group rule that drives all inbound internet traffic expect port 443
D. Network ACL rule that allows port 443 inbound and all ports outbound for internet traffic
E. Security group rule that allows internet traffic for port 443 in both inbound and outbound
Answer: A,D

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